Question

Step-by-step explanation:

Given:-

Rate of Interest = 10%

Amount = Rs. 5445

Time = 2 years

And the Interest is compounded annually.

To Find:-

The sum invested (Principal)

Solution:-

Let the sum of money invested be ' P '

As we know that:-

The formula used for finding Amount is

\boxed{ \sf \bull \: Amount = P \bigg(1 + \frac{r}{100} \bigg)^{n} }∙Amount=P(1+100r​)n​

Here:-

• Amount = Rs.5445

• P = Principal = ?

• r = Rate of Interest = 10%

• n = time = 2 years

Substituting the values:-

\sf \implies 5445 = P \times \bigg(1 + \dfrac{10}{100} \bigg)^{2}⟹5445=P×(1+10010​)2

\sf \implies 5445 = P\times \bigg(\dfrac{100 + 10}{100} \bigg)^{2}⟹5445=P×(100100+10​)2

\sf \implies 5445 = P\times \bigg(\dfrac{110}{100} \bigg)^{2}⟹5445=P×(100110​)2

\sf \implies 5445 = P\times \bigg(\dfrac{11}{10} \bigg)^{2}⟹5445=P×(1011​)2

\sf \implies 5445 = P\times \dfrac{11 \times 11}{10 \times 10}⟹5445=P×10×1011×11​

\sf \implies 5445 = P\times \dfrac{121}{100}⟹5445=P×100121​

\sf \implies P = 5445\times \dfrac{100}{121}⟹P=5445×121100​

\sf \implies P = 45\times 100⟹P=45×100

\sf \implies P = 4500⟹P=4500

\underline{\boxed{\sf \therefore The \: sum \: invested\: (Principal) = Rs.4500}}∴Thesuminvested(Principal)=Rs.4500​​

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Answer 1

Answer:

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Answer 2

Answer:

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Explanation:

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