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▶ Given :
i) 3x + 2y = 20
ii) xy = 11 / 9
▶ To Find : 27x^3 + 8y^3
▶ According to the Question :
27x^3 = ( 3x )^3
8y^3 = ( 2y )^3
We know that :
a^3 + b^3 = ( a + b )^3 - 3ab ( a + b )
( 3x )^3 + ( 2y )^3 = ( 3x + 2y )^3 - 3 × 3x × 2y ( 3x + 2y )
( 3x )^3 + ( 2y )^3 = ( 20 )^3 - 18xy ( 20 )
( 3x )^3 + ( 2y )^3 = 8000 - 18 × 11 / 9 × 20
( 3x )^3 + ( 2y )^3 = 8000 - 440
( 3x )^3 + ( 2y )^3 = 7560
✔✔ Hence, it is solved ✅✅
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