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Given :
- A tree breaks due to storm.
- The broken part from the top touches the ground making an angle of 30° with ground.
- The distance between foot of tree to the point where the broken bent part touches the ground is 8 m.
To Find :
- Initial Height of the Tree.
Solution :
AC = x m = The portion from where the tree remained unbroken.
CB = y = The broken portion of the tree after the storm.
AB = 8 m = Distance between the foot of the tree and the point where the broken part touches the ground.
Consider Δ ABC.
AC = x m
AB = 8 m.
= 30°
Using,
Block in the data,
Now, in Δ ABC.
AB = 8 m
CB = y m.
Using,
Block in the data,
AC = x = 8/√3 m
CD = y = 16/√3 m.
Height of the tree is the sum of AC and CD.
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