Steve bought two buffaloes for Rs. 30,000. By selling one at a loss of 15% and other at a profit of 19%, he found that selling price of both buffaloes is the same. Find the C.P of each.
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Let the cost price of the buffaloes be x and y.
Given that he bought buffaloes for 30000.
x + y = 30000 --- (1).
Given that he sells at a loss at 15%. Then SP of 1st buffalo = 85x/100.
Given that he sells at a profit of 19%.Then SP of 2nd buffalo = 119y/100.
Given that SP of both buffaloes is same, 85x/100 = 119y/100
x = 1.4y --- (2)
Substitute (2) in (1), we get
1.4y + y = 30000
2.4y = 30000
y = 12500.
Substitute y = 12500 in (1), we get
x + 12500 = 30000
x = 17500.
The cost price of 1st buffalo = 17500.
The cost price of 2nd buffalo = 12500.
Hope this helps!
Given that he bought buffaloes for 30000.
x + y = 30000 --- (1).
Given that he sells at a loss at 15%. Then SP of 1st buffalo = 85x/100.
Given that he sells at a profit of 19%.Then SP of 2nd buffalo = 119y/100.
Given that SP of both buffaloes is same, 85x/100 = 119y/100
x = 1.4y --- (2)
Substitute (2) in (1), we get
1.4y + y = 30000
2.4y = 30000
y = 12500.
Substitute y = 12500 in (1), we get
x + 12500 = 30000
x = 17500.
The cost price of 1st buffalo = 17500.
The cost price of 2nd buffalo = 12500.
Hope this helps!
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