Stomach acid is a solution of HCl with concentration of 1.2 × 10–3 M. What is the pH of stomach acid?
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Answered by
4
concentration of HCl C = 1.2×10^-3
pH = -log[C]
= -log(1.2×10^-3)
= -[log1.2 + log10^-3]
= -[0.079 - 3log10]
= -[0.079 - 3]
pH = 2.921
pH = -log[C]
= -log(1.2×10^-3)
= -[log1.2 + log10^-3]
= -[0.079 - 3log10]
= -[0.079 - 3]
pH = 2.921
Answered by
0
concentration of HCl C = 1.2×10^-3
pH = -log[C]
= -log(1.2×10^-3)
= -[log1.2 + log10^-3]
= -[0.079 - 3log10]
= -[0.079 - 3]
pH = 2.921
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