Question

stone is thrown vertically upwards it reaches its maximum height in 3 seconds if the acceleration of the stone be 9.8 mm - 2 square direct towards the ground calculate the initial velocity of the stone with which it is thrown upwards find the maximum height attained by it​

Answer 1

Answer:

Explanation:

Initial velocity of the stone, u = ?

Final velocity of stone, v = 0

Acceleration due to gravity, g=−9.8m/s  

2

 

Time, t = 3 sec

Using relation, v = u + gt

0=u−9.8×3

u = 29.4 m/s