stone is thrown vertically upwards with a velocity of 4.9 metre per second calculate the maximum height reached
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Answered by
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v^2 - u^2=2as
0^2 - (4.9)^2= 2*(-9.8)*s ------------taking the scene of stone moving up only
-24.01=-19.6s
s=1.225 metres
hope this helps!
0^2 - (4.9)^2= 2*(-9.8)*s ------------taking the scene of stone moving up only
-24.01=-19.6s
s=1.225 metres
hope this helps!
hitarthgodhani:
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Answered by
8
Here is your answer dear
Hope you will be satisfied
Hope you will be satisfied
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