Question

Stone is thrown vertically upwards with a velocity of 4.9m/s calculate the maximum height the time taken velocity to the ground and the time taken to reach the ground

Answer 1

Hi..
Hope this helps u!

Answer 2

Answer:

Height=1.255m

Velocity= 0.5s

Time ,t=1s

Explanation:

Maxi height attained by the stone,(h) v²=u²-2gh

where, v⇒ final velocity=zero

            u⇒ initial velocity

            g⇒ acceleration due to gravity

hence h=u²/2g=(4.9×4.9)/(2×9.8)=1.255m

time taken to reach maxi height, v=u-g t

final velocity v=0, t=u/g=4.9/9.8=0.5s

stone reaches the ground with same velocity as it was projected upwards, v=4.9m/s

Time taken by the stone to reach upwards is same as time taken to reach downwards=0.5+0.5=1s