Stone thrown vertically upward with speed of 20m/s how high will it go before it began to fall
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u = 20m/s
v = 0m/s
Acceleration due to gravity is taken as negative. This is becaue, when the direction of motion of object is opposite to 'g', the "g" is taken as -ve.
Hence,
g=-9.8m/s^2
v^2 - u^2 = 2gh
0^2 - 20^2 = 2*-9.8*h
-400 = -19.6h
h = -400/-19.6
h = 400/19.6
h = 20.408 [Approximately].
HOPE IT IS CLEAR FOR YOU!!!
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