Question

Stone weighing 1kg is sliding at 2m/s and stopped by friction in 10sec. Find friction force?

Answer 1

Mass of the marble block, m=2kg. Initial velocity,uo=6m/s. time for velocity to become zero,t=10s

The frictional force=uN=umg. Here u is coefficient of friction. N is normal force of reaction. N=mg.

The retardation( a ) produced by this force=umg/m=ug……………(1). We can find retardation from the equation of motion:

0=uo-at or a=uo/t=6/10=0.6m/s^2…………………………..(2)

From (1) and (2),

ug=0.6. Then u=0.6/10=0.06 . This is coefficient of friction.

by mistake i changed the statement but you put your values and apply the same formula like i have done and please mark it as brainliest

Answer 2

Frictional force = u. N


AS, the body is sliding N =mg cos ©
= 1 *10 cos ©
©= thetha = 10 cos ©

V = U +at
2=a *10
a =0.2 m/sec^2
and ; a = gsin©
Therefore, gsin©=0.2

Therefore, mgsin© = frictional force
=0.2 =frictional force


Hope will help you!