Question

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Calculate the electrostatic energy
Parallel plate capacitor of plate area 1 cm2
sa parcate by a
a distance of 0.01 m and connected
to a 4- volt cell.​

Answer 1

Answer:

210v

Explanation:

Above a particular electric field, of dielectric strength say Eds, the dielectric in a capacitor becomes conductive. The voltage at which this occurs is called the breakdown voltage of the device, and is given by the product of the dielectric strength and the separation between the conductors.

Thus we get Vbd=Edsd

Thus we get

Eds=3×106=dVbd

or Vrms=2Vbd=23×106×10−4=210V

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