Question

story of 1 kg is thrown with a velocity of 20 metre per second across the frozen surface of a lake and comes to rest after travelling a distance of 50 metre what is the force of friction between stone and ice​

Answer 1

Answer:

m=1kg

u=0m/s

v=20m/s

s=50m

2as=v^2

a=4m/s^2

f=ma

f=200N

f(friction )=-200N

Explanation:

every action has equal and opposite reaction

since force applied by object is 200N hence friction is -200N