Chemistry, asked by gaurav9352840209, 10 months ago

stoveture of XeF6 with method of Preb​

Answers

Answered by kshitizbitu7256
2

Answer:

  1. XeF6 can be prepared by heating a mixture of xenon and fluorine in the ratio 1:20 in a nickel vessel at 600 K under 60–70 bar pressure.
  2. It can also be obtained by reacting XeF4 with O2F2 at −130°C.
  3. It is a strong fluorinating and oxidising agent.
  4. With HF, it gives an ionic compound [XeF5]+[HF2]−.
Answered by Anonymous
2

Answer:

It is a compound of xenon with fluorine. Xenon exhibits +6 oxidation state in this compound.

Preparation:

  • XeF6 can be prepared by heating a mixture of xenon and fluorine in the ratio 1:20 in a nickel vessel at 600 K under 60–70 bar pressure.
  • It can also be obtained by reacting XeF4 with O2F2 at −130°C.

  • It is a strong fluorinating and oxidising agent.
  • With HF, it gives an ionic compound [XeF5]+[HF2]−.

  • On heating, it decomposes to give XeF2 and XeF4.

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