Question

Straight conductor 2m long carrying a current of 10A is kept at right angles to a uniform magnetic field of induction 3 ×10^-3 Wb/m^2. What is force acting upon it?​

Answer 1

Answer:

For a straight conductor, F= Bilsin theta

Or                                      F= 3( 10 *-3) (10) (2) sin 90

Or                                      F= 0.06 N