Question

straight distance between a hotel and railway station is 10 km but circular path is followed by taxi cover in 23km in 28 min find average velocity and average speed

Answer 1

average speed=total distance/time=23/28 km/min.
total displacement=10km.
so time taken wi

Answer 2

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a) Total distance travelled = 23 km

Total time taken = 28 min= 28/60 h

. ' . Average speed of the taxi

= total distance traveled/ total time taken

= (23 ) / (28/60) =49.29 km/h

b) Distance between the hotel and the station

= 10 km

= Displacement of the car

. ' . Average velocity

= (10)/(28)60)

= 21.43 km/h

Therefore, the two physical quantities (average speed and average velocity) are not equal

I hope, this will help you

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