Math, asked by aadarshdas16, 5 months ago

straight line paralled to y-axis
a find the equation of a
lying
at a distance of
i 5 units left of y-axis​

Answers

Answered by anjali5087
7

Answer:

HEY MATE HERE IS UR ANSWER

Let AB be a straight line parallel to y-axis at a distance a units from it. Then, clearly, all points on the line AB have the same abscissa a. Thus, AB can be considered as the locus of a point at a distance a from y-axis and all points on the line AB satisfy the condition x = a.

Thus, if P(x, y) is any point on AB, then x = a.

Hence, the equation of a straight line parallel to y-axis at a distance a from it is x = a.

The equation of y-axis is x = 0, since, y-axis is a parallel to itself at a distance 0 from it.

Or

Let P (x, y) be any point on the y-axis. Then clearly, for all position of P we shall the same abscissa 0 or, x = 0.

Therefore, the equation of y-axis is x = 0.

If a straight line is parallel and to the left of x-axis at a distance a, then its equation is x = -a.

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aadarshdas16: May I have it's exact answer
Answered by AlastorMadEyeMoody
3

Answer:

y = -5

Step-by-step explanation:

Equation of a line parallel to y axis is calculated using y = mx + c formula.

here m = 0 and c = -5

thus,

y = mx + c becomes

y = 0 + (-5)

y = -5

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