straight line with a velocity of 10 ms-1 collides with, and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the before the impact and just after the impact. Also, calculate the velocity of the combined object.
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Answer:
m = 1kg,
u1=10ms−1
M=5 kg and
u2= 0ms−1
Explanation:
From conservation of momentum
Initial momentum = final momentum
mu1 + Mu2 = (m+M)v
1×10 + 5×0 = (1+5)v
10=6v
Hence, the velocity of both is v =5/3ms−1
Total momentum before is 10 kgms−1
From momentum conservation, total momentum after is 10kgms−1.
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