Physics, asked by 03singhshreya, 11 months ago

strain energy=1/2(load).(extension)​

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Answered by krrish9287
7

Answer:

e.g., Y = stress/strain. if we assume a wire of length L, area of cross section A is fixed at one end and stretched by suspended a load M from the other end due to this extension of wire is x. = 1/2 × load × extension. F = YA / L x .

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