The sum of 3 consecutive terms of AP is 21and sum of squares of terms is 165.find the terms.(important consecutive terms)
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Let the 3 terms be a-d,a,a+d
According to question:-
a-d+a+a+d=21
3a=21
a=7
Now,(a-d)²+(a)²+(a+d)²=165
(7-d)²+(7)²+(7+d)²=165
49+d²-14d+49+49+d²+14d=165
147+2d²=165
2d²=165-147
2d²=18
d²=18/2
d²=9
d=3
Hence,the terms are:-
7-3,7,7+3
4,7,10
Jaspreetk04:
plz mark as Brainlist
dear their is mistake in your sum
first term will be a, not A-ha d
first term will be a
not a - d
For 3 consecutive terms in AP {a-d,a,a+d} this is the only formula
the answer is correct i am sure
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