Question

Student B starts at the origin 'O'. He travels 5 km north. He turns left and walks 15 km west. Next, he turns left again and walks 20 km south. How far is student B from the origin​

Answer 1

Explanation:

• Hy good morning how are you

Answer 2

answer:root 250 =15.8km

Explanation:

1. first travel 5 km north which is posotive Y axis, next walks 15 km south which is negative X axis. next walks 20 km left which is negative Y axis. here we find 5 pints A(0,0), B(0,5), C(-15,5),D(0,-15),E(-15,-5).
2. on the graph AB=5km, BC=15Km AC=?.
3. from triangle law of hypotenus,
4. $ab {}^{2} + bc {}^{2} = ac {}^{2}$
5. $5 {}^{2} + 15 {}^{2} = ac { }^{2} \\ 25 + 225 = ac {}^{2} \\ ac {}^{2} = 25 \\ ac = \sqrt{250} = 15.8km$
6. from similar triangle concept AC=AE=15.8 KM
7. There fore student B is at 15.8 km away from origin in 3 rd quardinate of graph representation.