Question

Students of a class are arranged in rows and columns. If there are 5 less rows, then there are 10 more number of columns formed and if there are 5 more rows, then number of columns formed are reduced by 5. The total number of students in the class are plz tell guys and dont spam or else iwill report

Answer 1

Answer:

r=15

c=20

Step-by-step explanation:

r= no. of rows

c=no. of columns

X=total students

r×c=X

(r-5)×(c+10)=X

(r+5)×(c-5)=X

solve these simultaneous equations,we get

10r-5c-50=0

-5r+5c-25=0

5r=75,

r=15

c=20

Answer 2

Given  : Students of a class are arranged in rows and columns. If there are 5 less rows, then there are 10 more number of columns formed and if there are 5 more rows, then number of columns formed are reduced by 5.

To find : total number of students in the class

Solution:

Let say number of rows =  R

& Number of columns  = C

Total Students  = RC

If there are 5 less rows, then there are 10 more number of columns formed

=  ( R - 5) (C + 10)

= RC  - 5C + 10R  - 50

RC  - 5C + 10R  - 50 = RC

=> 10R - 5C = 50

=> 2R - C  = 10   Eq1

if there are 5 more rows, then number of columns formed are reduced by 5

= ( R + 5) (C - 5)

= RC  + 5C - 5R  - 25

RC  + 5C - 5R  - 25  = RC

=>  5C - 5R = 25

=> C - R  = 5    Eq2

Eq1  + Eq2

=> R =  15

C = 20

Students = RC = 15 * 20  = 300

total number of students in the class   = 300

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