Students were standing in a row if one student is extra in a row there would be 2 rows less if one student is less in a row there would be 3 rows more
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Let the original number of rows =x
Let the original number of students in each row =y
Total number of students in class = Number of students × Number of rows =xy
According to problem
Case 1
Total no of students =(y+1)(x−2)=xy
⇒xy−2y+x−2=xy
⇒x−2y=2 ...(1)
Case 2
Total no of students =(y−1)(x+3)=xy
⇒xy+3y−x−3=xy
⇒x−3y=−3 ...(2)
Subtracting eq(1) from eq(2) we get
−y=−5
⇒y=5
Putting the value of y in eq(1)
x−2(5)=2
⇒x=12
Hence we get x=12 and y=5
Total no. of students =xy=60
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Answer: 60
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