Question

Study the circuit diagram and find :

(i) Current through each resistor

(ii) Ammeter reading



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Answer 1

Given :

Two resistors of 3Ω and 6Ω are connected in parallel across a battery of 10V.

To Find :

• Current through each resistor
• Ammeter reading

Solution :

❖ First of all we need to find equivalent resistance of the circuit.

Here both resistances are connected in parallel$.$

➙ 1/R = 1/R₁ + 1/R₂

➙ 1/R = 1/6 + 1/3

➙ 1/R = 3/6

➙ R = 6/3

➙ R = 2 Ω

Let's find net current flow in the circuit.

As per ohm's law, V = I × R

➛ V = I × R

➛ 10 = I × 2

➛ I = 10/2

➛ I = 5A (Reading of ammeter)

❒ Current through 6Ω :

➠ V = I₁ × R₁

➠ 10 = I₁ × 6

➠ I₁ = 10/6

➠ I₁ = 1.67A

❒ Current through 3Ω :

➠ I₁ + I₂ = I

➠ 1.67 + I₂ = 5

➠ I₂ = 5 - 1.67

➠ I₂ = 3.33 A

Answer 2

Given

a circut

2 resistors of value 6 ohm and 3ohm are connected in parallel arrangement.

voltage = 10 V

To find

(i) Current through each resistor

(ii) Ammeter reading

Solution

current showing in ammeter = 5 Ampere

current in 6 ohm resistor = 1.67 Ampere

current in 3 ohm resistor = 3.33 Ampere

refer to the attachment for the explanation.

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know More !!!

✏️A circuit is composed of conductors (wire), power source, load, resistor and switch.

✏️Resistors control the flow of the electric current in a circuit.

✏️A circuit is said to be connected in series when the same amount of current flows through the resistors.

✏️The following relation gives the total resistance of a series circuit:

$\sf \purple{ \bold{ R_{eq} = R_{1}+ R_{2} +..... + R_{n}}}$

✏️A circuit is said to be connected in parallel when the voltage is the same across the resistors.

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