Chemistry, asked by nisha02345, 2 months ago

Study the diagram given below and answer the questions that follow it:

(a) Which defect of vision is represented in this case? Give reason for your answer.
(b) What could be the two causes of this defect?
(c) With the help of a diagram show how this defect can be corrected by the use of a suitable lens. ​

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Answers

Answered by loparathod2609
6

Answer:

(a) The figure depicts myopia defect also known as nearsightedness

(b) The possible reason for this defect is:

     (1) It occurs when the eye grows too long from front to back as instead of focusing on the retina the lens of the eye focuses the image in front of the retina

     (2) It can also occur when the cornea is too curved for the length of the eyeball or a lens that is too thick.

(c) The parts labelled in the diagram are as follows:

1. is vitreous humour

2. is the blind spot

3. is Lens

4. is Pupil

(d) The lens used to correct myopia is a concave lens, the concave lens diverge the light rays, and as a result, the image will form on the retina.

(e) The attached figure shows how myopia is rectified

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Answered by naman1465
51

(a) Hypermetropia as the image is formed beyond the retina.

(a) Hypermetropia as the image is formed beyond the retina. (b) (i) Due to greater focal length of the , lens and (ii) As eyeball becomes smaller.

(a) Hypermetropia as the image is formed beyond the retina. (b) (i) Due to greater focal length of the , lens and (ii) As eyeball becomes smaller. (c) It can be corrected by using a convex lens of suitable focal length as shown below.

(a) Hypermetropia as the image is formed beyond the retina. (b) (i) Due to greater focal length of the , lens and (ii) As eyeball becomes smaller. (c) It can be corrected by using a convex lens of suitable focal length as shown below.

ÇUTIE ❤️

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