Question

Study the following velocity time graph . Determine the displacement and distance in the time interval t = 0 to t= 12s . Sketch the acceleration time graph.

Please answer this if u knew the answer.
Don't give irrelative answers.. ​

Answer 1

Explanation:

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Answer 2

ANSWERS:

• Displacement = 25 m
• Distance = 53 m

SOLUTION:

Refer to the given five attachments.

DISPLACEMENT:

• Area under velocity time graph gives displacement.

• Displacement = Area of velocity time graph = 25 m

DISTANCE:

• Velocity time graph and speed time graph are same expect for the negative velocity time graph.

• The negative velocity time graph becomes positive in speed time graph.

• Area under speed time graph gives distance.

• Distance = Area of speed time graph = 53 m

ACCELERATION:

• Slope of velocity time graph gives acceleration.

• The negative slope of velocity time graph gives negative acceleration.

• Since the velocity has a straight line, the acceleration is constant over that particular period.

• For time , t = 0 to t = 2 sec , a = 3 m/s²

• For time, t = 2 to t = 4 sec , a = 0 [There is no acceleration. It has constant velocity]

• For time, t = 4 to t = 5 sec , a = 6 m/s²

• For time t = 5 to t = 7 sec , a = -6 m/s²

• For time , t = 7 to t = 9 sec , a = -2 m/s²

• For time, t = 9 to t = 11 sec , a = 0

• For time, t = 11 to t = 12 sec , a = 4 m/s²