Study the given graph and answer the following questions from it :
Y
60-
B
с
40-
Velocity (km/h)
20-
(A E F D
X
0
2 3 4 5 6
Time (h) →
(i) Which part of the graph shows accelerated motion ? Calculate the acceleration.
(ii) Which part of graph shows retardation ? Calculate the retardation.
(iii) Calculate the distance travelled by the body in first two hrs. of journey graphically.
Answers
Answer:
Hope it will help you
Explanation:
Given graph is a VELOCITY-TIME graph of an object.
In VT graph:
1. The slope of the line at a particular time gives the acceleration of the object at that time.
2. Area under the graph gives the displacement of the object.
_______________________________
Coming to the questions:
1. Part AB is accelerated motion as the slope of the graph(which gives the acceleration) is positive.
acceleration = slope
So acceleration = 1 m/s^2
2.Part CD is retarded motion as the slope of the graph(which gives the acceleration) is negative.
So acceleration = -1 m/s^2
Thus retardation is 1 m/s^2
3.
distance of the body in first 4 seconds = area under graph from t=0 to t=4s
area under graph from t=0 to t=4s = area of ∆ABE = 1/2 × 4 × 4 = 8m
Thus distance of the body in first 4 seconds is 8m