Question

Study the time–distance graph given below for a car to travel to certain places and

answer the following questions:

(i) Calculate the average speed of the car in km/h.

(ii) Between which points is the speed of the car, the greatest?
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Answer 1

Answer:

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Step-by-step explanation:

Solution :

Solution : (a) Figuristaken along X - axi (a) Figure represents the distance - time graph of the car . Time is taken along X - axis and distance is taken along Y - axis.

(b) As the slope of distance - time graph represents speed , therefore , the line with maximum slope will represents maximum speed . As is clear from Fig , line CD represents maximum speed between 10.40am to

.( c ) Total distance travelled from 10.05 to 11.40am,s=42kmTotal time taken , t=11.40−10.05=1h35m=9560hAverage speed , vav=total distancetime taken=42km95/60h=26.5km/h

(d) Between 11.25am and 11.40am ,

distance travelled =42−38=4km

distance travelled =42−38=4kmspeed=distancetime=4km0.25h=16km/h

(e) Slowing down must give the car minimum speed (=12km/h) .

This is represented by line EF.

For this part, distance covered =11.10−11.00=10min=1060h=16h

For this part, distance covered =11.10−11.00=10min=1060h=16hspeed =distancetime=2km1/6h=12km/h.

Thus the car was forced to slow down to 12km/h at distance ranging from 26km to 28km.

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