Physics, asked by aditya693633, 4 months ago

Study the Velocity-Time graph below and answer the following:







a) What is the Acceleration between 0-5 seconds


b) What is the Acceleration between 5-15 seconds


c) What is the velocity in the 4th second


d) What is the displacement between 5-15 seconds


e) What is the total distance travelled​

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Answers

Answered by 0dhruvsingh
0

Answer:

a) Accceleration = 4 m/s

b) Acceleration = 0 m/s

c) Velocity = 16 m/s

d) Displacement = 200 m

e) Not sure , because Pic You Have Taken is Cropped but I took 20 sec as last of the graph.

- Distance = 300 m

Explanation:

a) Acceleration = Final - Initial Velocity / Time

Therefore,

a = v - u / t

a = 20 - 0 / 5

a = 4 m/s

b) Constant Velocity or Uniform Velocity

Therefore, No Acceleration

c) Velocity In 4th second would be 16 m/s

Because We know acceleration between 0 to 5 sec is 4m/s

Therefore,

v = u + at

v = 0 + 4 × 4

v = 16 m/s

d) Displacement between 5 to 15 secs would be Area of Rectangle. Because we know that In Velocity -Time Graph area under the stats is distance travelled.

Therefore,

Area Of Rectangle = L × B

= 10 × 20

= 200 m

e) As I said that area under velocity-time graph is distance travelled.(I took 20 secs as last of question/graph)

Therefore,

Area Of Trapezium = 1/2 × Sum Of Parallel Sides × Height

= 1/2 × (10+20) × 20

= 300 m

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