Study the velocity time graph of an ascending passenger lift in given figure along side. Which physical quantity is measured by area under quadrilateral ABCD then calculate it.
Attachments:
Answers
Answered by
46
check my bio and follow me i can help more
mark it as brainliest if possible
mark it as brainliest if possible
Attachments:
princessawesome:
Thank you so much but can you explain this its a request
Hi.Check youtube channel corephysics. It gives insight to physics concepts with problems.
Quick lessons for iit jee
@NITian
Quick lessons for iit jee
@NITian
check it i have explained
Ok
Thanks
Answered by
44
In velocity time graph , time is taken on the X axis and velocity on the Y axis.
The area enclosed between the velocity time graph gives displacement of body.
Displacement = velocity x time.
Area of quadrilateral ABCD:
As it is a rectangle, we have area as :
Area = lxb
= 8x4.6
=36.8m
Therefore displacement under area ABCD IS 36.8m
The area enclosed between the velocity time graph gives displacement of body.
Displacement = velocity x time.
Area of quadrilateral ABCD:
As it is a rectangle, we have area as :
Area = lxb
= 8x4.6
=36.8m
Therefore displacement under area ABCD IS 36.8m
Similar questions