studying at night guys so help me out and follow
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Step-by-step explanation:
Object height (h) = 2cm
Object distance (u) = -15 cm
Focal length (f) = -10 cm
[Object distance and focal length are taken negative in Concave mirror;New Cartesian Sign Convention]
We know, 1/v + 1/u = 1/f [Mirror formula]
Therefore, 1/v = 1/f - 1/u
1/v = 1/(-10) - 1/(-15)
1/v = 1/(-10) + 1/15 [(-) x (-) = (+)]
1/v = 5/(-150) [Cross-multiplying]
v = -150/5 = -30 cm
Image is -30 cm in front of mirror.
m = h'/h = -v/u [Formula of magnification]
Therefore,h' = (-v/u) * h
h' = -(-30) x (2)/(-15)
h' = -4 cm
Image is real,inverted and enlarged.
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