Math, asked by jassisudan630, 2 months ago

SU
Class surength?
1. Baichung's father is 26 years younger than Baichung's grandfather and 29
older than Baichung. The sum of the ages of all the three is 135 years. What is the
age of each one of them?

Answers

Answered by girirajchand49
0

Step-by-step explanation:

hmmm good quesstion you have aa very good question

Answered by Anonymous
0

Answer:

Given :

Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .

The sum of the age of all the three is 135 years.

Solution :

\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}

\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}

A.T.Q :

\longmapsto\tt{x+x-26+x-55=135}

\longmapsto\tt{3x-81=135}

\longmapsto\tt{3x=135+81}

\longmapsto\tt{3x=216}

\longmapsto\tt{x=\cancel\dfrac{216}{3}}

\longmapsto\tt\bf{x=72}

Value of x is 72 .

Therefore :

\longmapsto\tt{Age\:of\:his\:Grandfather=x}

\longmapsto\tt\bf{72\:yrs}

\longmapsto\tt{Age\:of\:his\:Father=72-26}

\longmapsto\tt\bf{46\:yrs}

\longmapsto\tt{Age\:of\:Baichung=72-55}

\longmapsto\tt\bf{17\:yrs}

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