Question

Subba Rao started work in 1995 at 10 annual salary of 5000 rupees and received and increment of rupees 200 each year in which year did his income reach 7000 ​

Answer 1

Answer: After 11 years = 2006

Step-by-step explanation:

Let us take an= 7000

a= 5000

d= 200

By applying formula

an = a + (n-1)d

7000=5000+(n-1)200

200n-200= 2000

n-1= 10

n=11

So his salary will be 7000 after 11 years that is 2006

Answer 2

11th Year

Given:

First Term of the AP(a) = 5000

Common Difference of the AP(d) = 200

The n th term of the AP(an) = 7000

The Formula that is used to find the n th term of the AP is:

An = a + (n - 1) d

Substituting the values known to us in this formula we get:

7000 = 5000 + (n - 1)200

7000 - 5000 = (n - 1) 200

2000 / 200 = n - 1

10 = n - 1

Taking 1 to the other side:

n = 10 + 1

n = 11

Therefore, from this we understand that in the 11th year his salary would be 7000 Rupees.