Math, asked by aadityapandey938, 5 hours ago

SUBJECT - Mathematics
CLASS - 10
TOPIC - Trigonometry
\large{\sf{\underline{QUESTION:-}}}
QUESTION:−


If 2 sin θ = 2 - cos θ and 0° < θ < 90°. Then, Find the value of sin θ.

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Answers

Answered by Sanskar260
0

Answer:

x= 3/5

Step-by-step explanation:

2 sin x = 2 - cos x

cos x = 2 - 2 sin x

Squaring both sides,

cos²x = 4 + 4 sin²x - 8 sin x

1 - sin²x = 4 + 4 sin²x - 8 sin x

5 sin²x - 8 sin x + 3 = 0

5 sin²x - 5 sin x - 3 sin x + 3 = 0

5 sin x(sin x - 1) - 3(sinx -1) = 0

(sin x - 1)(5 sin x - 3) = 0

sin x = 1, or sin x = 3/5

For 0° < x < 90°, sin x can't be equal to 1

Therefore, sin x = 3/5

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