SUBJECT - Mathematics
CLASS - 10
TOPIC - Trigonometry
\large{\sf{\underline{QUESTION:-}}}
QUESTION:−
If 2 sin θ = 2 - cos θ and 0° < θ < 90°. Then, Find the value of sin θ.
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Answer:
x= 3/5
Step-by-step explanation:
2 sin x = 2 - cos x
cos x = 2 - 2 sin x
Squaring both sides,
cos²x = 4 + 4 sin²x - 8 sin x
1 - sin²x = 4 + 4 sin²x - 8 sin x
5 sin²x - 8 sin x + 3 = 0
5 sin²x - 5 sin x - 3 sin x + 3 = 0
5 sin x(sin x - 1) - 3(sinx -1) = 0
(sin x - 1)(5 sin x - 3) = 0
sin x = 1, or sin x = 3/5
For 0° < x < 90°, sin x can't be equal to 1
Therefore, sin x = 3/5
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