Question

substract the sum of 1/4 and -3/8 from additive inverse of (-3/8)-(-2/7)​

Answer 1

$\sf \: Subtract \: the \: sum \: of \: \dfrac{1}{4 \: } and \: \dfrac{ - 3}{8} \: from \: the \: additive \: inverse \: of \: \bigg( \dfrac{ - 3}{8} \bigg) - \bigg( \dfrac{ - 2}{7} \bigg)$

$\sf \: \underline{ \underline{Let's \: find \: our \: answer}}..$

$\sf \: First \: of \: all \: we \: will \: find \: the \: sum \: of \: \dfrac{1}{4 \: } \: and \: \dfrac{ - 3}{8}$

$\sf \implies \: \dfrac{1}{4 \: } \: + \: \dfrac{ - 3}{8}$

$\sf \implies \: \dfrac{1}{4 \: } \: - \: \dfrac{ 3}{8}$

$\sf \implies \: \dfrac{2 - 3}{8}$

$\sf \implies \: \dfrac{-1}{8}$

$\sf \: So, \: sum \: of \: \dfrac{1}{4 \: } \: and \: \dfrac{ - 3}{8} \: is \: \red{ \dfrac{-1}{8}}$

$\sf \: \underline{ According \: to \: question},$

$\sf \: We \: have \: to \: Subtract \: \dfrac{-1}{8} \: from \: the \: additive \: inverse \: of \: \bigg( \dfrac{ - 3}{8} \bigg) - \bigg( \dfrac{ - 2}{7} \bigg)$

$\sf \: Now, \: we \: will \: find \: the \: additive \: inverse \: of \: \bigg( \dfrac{ - 3}{8} \bigg) - \bigg( \dfrac{ - 2}{7} \bigg)$

$\sf \implies\bigg( \dfrac{ - 3}{8} \bigg) - \bigg( \dfrac{ - 2}{7} \bigg)$

$\sf \implies \: \dfrac{ - 3}{8} + \dfrac{ 2}{7}$

$\sf \implies \: \dfrac{ - 21 + 16}{56}$

$\sf \implies \: \dfrac{ - 5}{56}$

$\sf \: Additive \: inverse \: of \:\dfrac{ - 5}{56} \: = \: \red{ \dfrac{5}{56} }$

$\sf \: Now, \: we \: have \: to \: subtract \: \dfrac{-1}{8} \: from \:\dfrac{5}{56}$

$\sf \implies \: \:\dfrac{5}{56} - \dfrac{-1}{8} \:$

$\sf \implies \: \:\dfrac{5}{56} + \dfrac{1}{8} \:$

$\sf \implies \: \:\dfrac{5 + 7}{56}$

$\sf \implies \: \:\dfrac{ 12}{56}$

$\boxed{ \pink{ \sf \: Answer \: = \: \dfrac{3}{14}}}$