Subtopic :Operations on rational numbers.
Description : Twenty caravans are
travelling across the desert one day
apart. The first caravan reached the oasis
and the camels drank half of the water in
the pool. On the second day, the second
caravan reached the oasis and the camel
drank one-third of the water that was left.
On the third day, the camels in the third
caravan drank one-quarter of the water
that was left. On the first day the pool
contained 1050m of water. How much
water was left after the 20th caravan
passed through
HINT : Observe the pattern and calculate.
Answers
Answered by
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1/21 or 50
water was left after the 20th caravan passed through.
Step-by-step explanation:
Given that,
Water in the pool on the first day = 1050 m^3
Water left by the first caravan = 1/2
Water left by the second caravan = 2/3 * 1/2 = 2/6 = 1/3 (∵ 3/3 - 1/3 = 2/3)
Similarly,
Water left by the third caravan = 3/4 * 1/3 = 1/4 (∵ 4/4 - 1/4 = 3/4)
Following the pattern:
Water left by the caravan on the 21st day = 1/21
now,
1/21 of 1050 m^3
= 1/21 * 1050
= 50 m^3
Thus, 1/21 or 50 m^3 is the water that was left post 20th day of the caravan.
Learn more: Complete the pattern
brainly.in/question/17015539
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