Question

Subtract 1- b square - 3b cube, 2b square + b cube + 3
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Answer 1

Answer:

Your answer is -2b^3-b^2-1

$(1 - {b}^{2} - 3 {b}^{3} ) - (2 {b}^{2} + {b}^{3} + 3) \\ = (1 - {b}^{2} - 3 {b}^{3} ) - 2 {b}^{2} - {b}^{3} - 3 \\ = - 3 {b}^{3} - {b}^{3} - {b}^{2} - {b}^{2} + 1 - 3 \\ = - 4 {b }^{3} - 2 {b}^{2} - 2 \\ = 2 \: ( - 2 {b}^{3} - {b}^{2} - 1) \\ or \\ = - 2 {b}^{3} - {b}^{2} - 1$