Math, asked by sanjaysingh05749, 8 months ago

Subtract 1- b square - 3b cube, 2b square + b cube + 3

Answers

Answered by akchaudhary84
0

Answer:

Your answer is -2b^3-b^2-1

(1 -  {b}^{2}  - 3 {b}^{3} ) - (2 {b}^{2} +  {b}^{3}   + 3) \\  = (1 -  {b}^{2}  - 3 {b}^{3} ) - 2 {b}^{2}  -  {b}^{3}   - 3 \\  =  - 3 {b}^{3}  -  {b}^{3}  -  {b}^{2}  -  {b}^{2}  + 1 - 3 \\  =  - 4 {b }^{3}  - 2 {b}^{2}  - 2 \\  = 2 \: ( - 2 {b}^{3}  -  {b}^{2}  - 1) \\ or \\  =  - 2 {b}^{3}  -  {b}^{2}  - 1

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