Subtract (2a-3b+4c) from the sum (a+b+c) and (-2a-3b+4c)
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Answered by
6
sum of (a+b+c) and (-2a-3b+4c) is -a-2b+5c
sub
so we get minis here (-) (-a-2b+5c) frm (2a-3b+4c) gives raise to
final answer is
(3a-b-c)
hpe it help mark as brainly
sub
so we get minis here (-) (-a-2b+5c) frm (2a-3b+4c) gives raise to
final answer is
(3a-b-c)
hpe it help mark as brainly
Answered by
1
(a+b+c)
+(-2a-3b-4c)
=_a-2b-3c
-(2a-3b+4c)
3a+b-c
+(-2a-3b-4c)
=_a-2b-3c
-(2a-3b+4c)
3a+b-c
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