Subtract (2a - 3b + 4c) from the sum of (a + 3b – 4c), (4a - b +9c) and (-2b + 3c - a).
of (2m + 4n-3p2)
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Answer:
2a + 3b + 4c
Step-by-step explanation:
(a + 3b – 4c) + (4a - b +9c) + (-2b + 3c - a)
- (2a - 3b + 4c)
= (a + 3b – 4c + 4a - b +9c - 2b + 3c - a)
- (2a - 3b + 4c)
= (4a + a - a + 3b - b - 2b - 4c + 9c + 3c)
- (2a - 3b + 4c)
= (4a + 8c) - (2a - 3b + 4c)
= 4a + 8c - 2a + 3b - 4c
= 4a - 2a + 3b + 8c - 4c
= 2a + 3b + 4c
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