Question

Subtract
2p(p+q-r) from 6q(p+q) + 7p(p-q-r)​

Answer 1

Step-by-step explanation:

so, 2p²+2pq+2pr from

6pq + 6q² + 7p² - 7pq - 7pr

now, 6pq + 6q² + 7p² - 7pq - 7pr

= -pq + 6q² + 7p² - 7pr ..

pq + 6q² + 7p² - 7pr

(-) 2p²+2pq+2pr

_________________

5p²-3pq-9pr+6q² --- answer

Answer 2

Answer:

Step-by-step explanation:

Answer:

-3pq+5p^2+6q^2-7pr+r

Step-by-step explanation:

[6q(p+q)+7p(p-q-r)]-2p(p+q-r)

=6pq-7pq-2pq+7p^2-2p^2+6q^2-7pr+r

=-3pq+5p2+6q2-7pr+r(Answer)