Subtract:{-2ysq +1/2y-3}from 7ysq -2y+10
tenzdoe:
Solve it
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Answered by
6
7y² - 2y+10 -( -2y² + 1/2y -3)
= 7y² - 2y+10 + 2y² - 1/2y + 3
= 7y²+ 2y² - 2y- 1/2y +10 + 3
= 9y² -(2y + 1/2y) +10 + 3
= 9y² - (y + 13
= 9y² - y + 13
= 9y² -y + 13
= 7y² - 2y+10 + 2y² - 1/2y + 3
= 7y²+ 2y² - 2y- 1/2y +10 + 3
= 9y² -(2y + 1/2y) +10 + 3
= 9y² - (y + 13
= 9y² - y + 13
= 9y² -y + 13
Answered by
3
so to do
7y² - 2y+ 10 - (-2y² +1/2y -3)
= 7y² - 2y+ 10 + 2y² - 1/2y + 3
= 9y² -5/2y +13
7y² - 2y+ 10 - (-2y² +1/2y -3)
= 7y² - 2y+ 10 + 2y² - 1/2y + 3
= 9y² -5/2y +13
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