Question

Subtract 3 1/7 from the sum of 4/21 and 2 3/14​

Answer 1

Answer:

Step-by-step explanation:

Given that,

The sum of 4/21 and 2 3/14=31/14

= 4/21 + 31/14

= ( 2 × 4 ) + ( 3 × 31 ) / 14

= ( 8 + 93 ) / 42 (∵ The lcm of 21 and 14 is 42.)

= 101 / 42

Now subtracting 3 1/7 = 22/7 from 101/ 42

= 101 / 42 - 22 / 7

= ( 1 × 101 ) - ( 6 × 22 ) / 42 (∵The lcm of 42 and 7 is 42. )

= ( 101 - 132 ) / 42

= - 31 / 42 is the answer.

Answer 2

Answer:

0

Step-by-step explanation:

According to the question,

the equation will be $(\frac{4}{21}+2\frac{3}{14}) - 3\frac{1}{7}$

• First change all whole fractions to improper fractions.

So, $(\frac{4}{21}+2\frac{3}{14}) - 3\frac{1}{7}$

= $(\frac{4}{21}+\frac{31}{14}) - \frac{22}{7}$

• Then make all the denominators equivalent.

So, $(\frac{4}{21}+\frac{31}{14}) - \frac{22}{7}$

= $(\frac{4}{21}+\frac{62}{21}) - \frac{66}{21}$

According to VBODMAS rule,

• First solve brackets.

$(\frac{4}{21} + \frac{54}{21})$

= $\frac{66}{21}$

• Now solve the subtraction.

So, $\frac{66}{21} - \frac{66}{21}$

= $\frac{0}{21}$ = 0

So, $(\frac{4}{21}+2\frac{3}{14}) - 3\frac{1}{7}$ = 0

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