SUBTRACT 3a(a+b+c)-2b(a-b+c) from 4c(-a+b+c)
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Step-by-step explanation:
4c(-a+b+c) -[ 3a(a+b+c)-2b(a-b+c) ]
= -4ac +4bc +4c^2 -( 3a^2 +3ab +3ac -2ab +2b^2 -2bc)
= -4ac +4bc +4c^2 -( 3a^2 +ab +3ac +2b^2 -2bc)
= -4ac +4bc +4c^2 -3a^2 -ab -3ac -2b^2 +2bc
= 4c^2 -3a^2 -2b^2 -7ac +6bc -ab
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