Question

There are 26 tuning forks arranged in the decreasing order of their frequencies . Each tuning fork gives 3 beats with the next the first one is octave of the last .What is the frequency of 18th tuning fork

Answer 1

There are four options provided in this question as a choice. Below are the four options:

( A ) - 100 Hz                                  

( B ) - 99 Hz

( C ) - 96 Hz                                    

( D ) - 103 Hz

According to the question mentioned above, the answer would be  ( B ) - 99 Hz

Answer 2

Answer:

99 Hz

Explanation:

Let the frequency of 1st tuning fork = f

Frequency of last turning fork = f/2

Also each tuning fork gives 3 beats with the next.

f - (25 x 3) = f/2

Solving, we get f = 150 Hz

So the frequency of 1st fork = 150 Hz

Frequency of 18th fork will be,

f(18) = f - 17 x 3 = 150 - 17 x 3 = 99 Hz