In a Young’s double slit experiment, the slit separation is 1 mm and the screen is 1 m from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd minima from the central maxima is(a) 0.50 mm(b) 1.25 mm(c) 1.50 mm(d) 1.75 mm
Answers
Answered by
5
Easy
Here you go
Subscribe to pewdiepie
Attachments:
Answered by
0
Answer:1.25mm
Explanation:
Similar questions