Physics, asked by sonty5254, 1 year ago

In a Young’s double slit experiment, the slit separation is 1 mm and the screen is 1 m from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd minima from the central maxima is(a) 0.50 mm(b) 1.25 mm(c) 1.50 mm(d) 1.75 mm

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Answered by bucksstar288
5

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Answered by jayantjayantjha
0

Answer:1.25mm

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