Subtract 3a ( a + b+ c ) – 2b( a – b + c ) from 4c ( -a + b + c )
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3a(a+b+c) -2b(a-b+c)
= 3a2 + 3ab +3ac -2ab + 2b2 -2bc
=3a2 +ab + 3ac + 2b2 -2bc
4c(-a+ b+c) =-4ac + 4bc +4c2
(-4ac + 4bc + 4c2) -(3a2 +ab + 3ac + 2b2 -2bc)
=-4ac +4bc+4c2 -3a2 -ab -3ac -2b2 +2bc
=(-4ac -3ac) + (4bc +2bc) +4c2 -3a2 -ab -2b2
= -7ac + 6bc +4c2-3a2-ab-2b2
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