Question

subtract 3a(a+b+c) -2b(a-b+c)from 4c(a+b+c)

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Answer 1

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Answer 2

$4c(a + b + c) - [3a(a + b + c) - 2b(a - b + c)] \\ = 4ac + 4bc + 4 {c}^{2} - [3 {a}^{2} + 3ab + 3ac - 2ab + 2 {b}^{2} - 2bc ] \\ = 4ac + 4bc + 4 {c}^{2} - 3 {a}^{2} - 3ab - 3ac + 2ab - 2 {b}^{2} + 2bc \\ = (4ac- 3ac) +( 4bc+2bc)+ 4 {c}^{2} - 3 {a}^{2} + ( - 3ab + 2ab)- 2 {b}^{2} \\ = ac + 6bc+ 4 {c}^{2} - 3 {a}^{2} - ab- 2 {b}^{2} \\ \\ \\ -3 {a}^{2}- 2 {b}^{2} + 4 {c}^{2} - ab + 6bc + ac \\ hope \: its \: correct...$