subtract 3a (a+b+c) from 4c(-a+b+c)
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Heya ✋
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3a(a + b + c) from 4c(-a + b + c)
= [4c(-a + b + c)] - [3a(a + b + c)]
= [-4ca + 4cb + 4c^2] - [3a^2 + 3ab + 3ac]
= -4ca + 4cb + 4c^2 - 3a^2 - 3ab - 3ac
= -4ca - 3ac + 4cb + 4c^2 - 3a^2 - 3ab
= -7ac + 4cb + 4c^2 - 3a^2 - 3ab
Thanks :)))
Let see your answer !!!
3a(a + b + c) from 4c(-a + b + c)
= [4c(-a + b + c)] - [3a(a + b + c)]
= [-4ca + 4cb + 4c^2] - [3a^2 + 3ab + 3ac]
= -4ca + 4cb + 4c^2 - 3a^2 - 3ab - 3ac
= -4ca - 3ac + 4cb + 4c^2 - 3a^2 - 3ab
= -7ac + 4cb + 4c^2 - 3a^2 - 3ab
Thanks :)))
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