Question

subtract 3a (a+b+c) from 4c(-a+b+c)

Answer 1

Heya ✋

Let see your answer !!!

3a(a + b + c) from 4c(-a + b + c)

= [4c(-a + b + c)] - [3a(a + b + c)]

= [-4ca + 4cb + 4c^2] - [3a^2 + 3ab + 3ac]

= -4ca + 4cb + 4c^2 - 3a^2 - 3ab - 3ac

= -4ca - 3ac + 4cb + 4c^2 - 3a^2 - 3ab

= -7ac + 4cb + 4c^2 - 3a^2 - 3ab





Thanks :)))