Question

subtract:
3a(a+b+c) from 4c(-a+b+c).

Answer 1

4c(b+c-a) - 3a(a+b+c)

= 4bc + $4 c^{2}$ - 4ac - $3a^{2}$ - 3ab - 3ac

= $4c^{2} - 3a^{2} - 7ac +4bc- 3ab$

Answer 2

The correct answer is "-3a²+4c²-3ab+4bc-7ac".

Step-by-step explanation:

$The \ given \ binomials \ are:\\\\3a(a+b+c) = 3a^2+3ab+3ac...(Equation 1)\\\\4c(-a+b+c)=-4ac+4bc+4c^2...(Equation 2)\\\\On \ subtracting \ (Equation 1) \ from \ (Equation 2),we \ get\\\\=-4ac+4bc+4c^2-(3a^2+3ab+3ac)\\\\=-4ac+4bc+4c^2-3a^2-3ab-3ac\\\\=-3a^2+4c^2-3ab+4bc-7ac$

Learn more:

https://brainly.in/question/2948830