Question

Subtract (3a2 bc) from ( - 13a2 bc + 5)​

Answer 1

Answer:

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Answer 2

Subtracting 3a²bc from - 13a²bc + 5 the result is - 16a²bc + 5

Given :

The expressions 3a²bc and - 13a²bc + 5

To find :

Subtract 3a²bc from - 13a²bc + 5

Solution :

Step 1 of 2 :

Write down the given expressions

The given expressions are 3a²bc and - 13a²bc + 5

Step 2 of 2 :

Subtract 3a²bc from - 13a²bc + 5

On subtraction we get

$\sf ( - 13 {a}^{2} bc + 5) - 3 {a}^{2} bc$

$\sf = - 13 {a}^{2} bc + 5 - 3 {a}^{2} bc$

$\sf = - 13 {a}^{2} bc- 3 {a}^{2} bc + 5$

$\sf =( - 13 - 3) {a}^{2} bc + 5$

$\sf = - 16 {a}^{2} bc + 5$