Question

subtract 3ab+4ac-a square +b cube from 7ac-2ab-5a square-b cube

Answer 1

Answer:

4c(-a+b+c) - [3a(a+b+c)-2b(a-b+c)]

=-4ac+4bc+4c²-[3a²+3ab+3ac-2ab+2b²-2bc]

=-4ac+4bc+4c²-3a²-3ab-3ac+2ab-2b²+2bc

write like terms at one place

=-4ac-3ac+4bc+2bc+4c²-3a²-2b²-3ab+2ab

=-7ac+6bc-ab+4c²-3a²-2b²

Answer 2

Answer:

4c(-a+b+c) - [3a(a+b+c)-2b(a-b+c)]

=-4ac+4bc+4c²-[3a²+3ab+3ac-2ab+2b²-2bc]

=-4ac+4bc+4c²-3a²-3ab-3ac+2ab-2b²+2bc

write like terms at one place

=-4ac-3ac+4bc+2bc+4c²-3a²-2b²-3ab+2ab

=-7ac+6bc-ab+4c²-3a²-2b²

Step-by-step explanation:

$hope \: it \: helped \: you \: friend$